Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].
class Solution {
public:
void rotate(vector<int>& nums, int k) {
k = k % nums.size();
reverse(nums.begin(), nums.end());
// 注意这里 vector 的 end()指向的是最后一个元素的下一个位置
// 而reverse 是一个左闭右开有始无终的操作
reverse(nums.begin(), nums.begin() + k);
reverse(nums.begin() + k, nums.end());
}
};